problem08_11

University Physics with Modern Physics with Mastering Physics (11th Edition)

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8.11: a) With , 0 1 = t , ) s N 10 00 . 2 ( ) s N 10 80 . 0 ( 3 2 2 9 2 2 7 0 2 t t dt F J t x x × - × = = which is 18.8 s m kg , and so the impulse delivered between t=0 and . i ˆ ) s m kg (18.8 is s 10 50 . 2 3 2 × = - t b) and s), 10 50 . 2 ( ) s m (9.80 kg) 145 . 0 ( 3 2 - × - = y J the impulse is j ˆ ) s m kg 10 55 . 3 ( 3 × - - c) 2 t J x =7.52 N, 10 3 × so the average force is (7.52 . i ˆ N) 10 3 × d) j p p + = 1 2 ) ˆ 10 55 . 3 ˆ (18.8
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Unformatted text preview: ˆ . 5 ˆ kg)(40.0 145 . ( 3 j i j i-×-+ +-= . j i ˆ kg.m/s) 73 . ( ˆ kg.m/s) . 13 (-= The velocity is the momentum divided by the mass, or (89.7 m/s) . j i ˆ m/s) . 5 ( ˆ-...
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