LAB REPORT #3

LAB REPORT #3 - Mentes Zorba LAB REPORT Experiment 3:...

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Mentes Zorba LAB REPORT Experiment 3: Electrical Properties of Metals Introduction The objective of this lab is to investigate the conductivity of several metals, compare them with each other and also determine how the conductivity varies with temperature. This is to be done by measuring the conductivity of 4 different metal samples at different temperatures and recording the values from each experiment. Experimental Procedure There are 4 samples of metals; Silicon, Germanium, Copper and Iron-Chromium (22%)-Aluminum (6%) Alloy. These samples are placed in special sealed test tubes which are filled with oil to avoid excessive heat loss and protect the electrodes. A digital multimeter is connected to the electrodes and the test tube is put into the water baths each time. The samples will be tested at 6 different temperatures. The water baths are prepared as follows 0ºC ice water, 25ºC water at room temperature, 50ºC water bath, 75ºC water bath, 100ºC boiling water and 125ºC glycerol. The test tube is allowed a few minutes until its resistance value on the multimeter reaches a steady value; it reaches the equilibrium temperature. At this point the values of resistance and temperature are recorded down.
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Results Results for Copper Temperature Resistance A/l Resistivity Conductivity Copper (C) (Ohm) (m) (Ohm m) (Ohm m) -1 T1 = 0 C 5 8.50 2.01E-09 1.71E-08 58513408.35 T2 = 25 C 21 9.00 2.01E-09 1.81E-08 55262663.44 T3 = 50 C 47 9.90 2.01E-09 1.99E-08 50238784.94 T4 = 75 C 72 10.60 2.01E-09 2.13E-08 46921129.34 T5 = 100 C 98 11.60 2.01E-09 2.33E-08 42876204.39 T6 = 125 C 117 12.00 2.01E-09 2.41E-08 41446997.58 Table 1: Experimental Data for Copper Resistivity Graph for Copper y = 6E-11x + 2E-08 R 2 = 0.9972 0.00E+00 5.00E-09 1.00E-08 1.50E-08 2.00E-08 2.50E-08 3.00E-08 0 50 100 150 Temperature(K) Resistivity (ohm.m) Resistivity Linear (Resistivity) Graph 1: Resistivity vs. Temperature Graph for Copper Copper is a conductive metal so its resistivity changes according to the following equation: In the graph for copper, the linear fit equation is y = 6E-11x + 2E-08 where b=2e-8 and m=6e-11. If we compare the these values with the resistivity equation, the values of ρ 0ºC = b and ρ 0ºC αT= m.
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So, ρ 0ºC =2E-08 and ρ 0ºC αT=6E-11 where α is the temperature resistivity coefficient for copper. When we divide the numbers, we get the result α=0.003. Results for Kanthal Alloy
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LAB REPORT #3 - Mentes Zorba LAB REPORT Experiment 3:...

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