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Homework 3 Answers Back You are encouraged to run PSpice and look at web sites during this homework quiz. It has 15 questions worth 1 point each. You can take it up to three times and we will take the maximum score. The questions review some things you should have learned in experiment 3 and also include some references to background you will need for experiment 4. Question 1 (1 point) Question 3-1a What is the formula for the inductance, L, of the coil shown on the left when R is the major radius of the coil, r is the radius of the wire, N if the number of windings of the coil, d is the length of the coil, and is the permeability constant of the core material? Student response: Percent Value Correct Response Student Response Answer Choices 100.0% a. L = ( N 2 R 2 ) / d 0.0% b. L = ( N R) / d 0.0% c. L = N 2 R{ln(8R/r)-2} 0.0% d. L = N 2 R{ln(4R/r)-1} General feedback: The equation for a long thin coil and a coin-shaped coil are given in the experiment. Score: 1 / 1 Question 2 (1 point) Question 3-1b What is the formula for the inductance, L, of the coil shown on the right when R is the major radius of the coil, r is the radius of the wire, N is the number of windings of the coil, d is the length of the coil, and is the permeability constant of the core material?

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Student response: Percent Value Correct Response Student Response Answer Choices 0.0% a. L = ( N 2 R 2 ) / d 0.0% b. L = ( N R) / d 100.0% c. L = N 2 R{ln(8R/r)-2} 0.0% d. L = N 2 R{ln(4R/r)-1} General feedback: The equation for a long thin coil and a coin-shaped coil are given in the experiment. Score: 1 / 1 Question 3 (1 point) Question 3-2 What is the resistance of 118 cm of 22 gauge (diameter = 0.643 mm) copper wire (conductivity = 6 x 10 7 Siemens/meter). Express your answer in ohms. Student response: 0.0606 Correct answer: 0.06057 General feedback: The correct formula for calculating the resistance of a wire based on cross sectional area, conductivity and length is given in the experiment writeup. It helps to convert everything to meters. Also remember that the formula for area is based on the radius, not the diameter. Score: 1 / 1 Question 4 (1 point) Question 3-3a What is the inductance of the coil pictured on the left when the number of turns is 48, the radius of the coil is 14 mm, the wire gauge is 22 (diameter=0.643 mm), the length of the coil is 6 cm and the core is made of iron ( =1200 x 4 x 10 -7 Henries/meter). Express your answer in millihenries.
Student response: 35.7 Correct answer: 35.67514 General feedback: The inductance formulas for both a long thin coil and a "coin=shaped" coil can be found in the experiment. Note that for an air core is 4 x 10 -7 and for the iron core, you multiply this standard by about 1200. The actual value depends on the individual core itself. Score: 1 / 1 Question 5 (1 point) Question 3-3b What is the inductance of the coil pictured on the right when the number of turns is 58, the major radius of the coil is 60 mm, the wire gauge is 22 (diameter=0.643 mm), the length of the coil is 0.5 cm, and the core is made of iron ( =1200 x 4 x 10 -7 Henries/meter). Express your answer in milliHenries.

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