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8.24:
Let Rebecca’s original direction of motion be the
x
direction. a) From
conservation of the
x
component of momentum,
,
kg)
0
.
65
(
53.1
m/s)cos
kg)(8.0
(45.0
m/s)
kg)(13.0
0
.
45
(
x
v
+
°
=
So
s.
m
67
.
5
=
x
v
If Rebecca’s final motion is taken to have a positive

y
component, then
s.
m
43
.
4
kg)
0
.
65
(
53.1
sin
s)
m
kg)(8.0
0
.
45
(

=
°

=
y
v
Daniel’s final speed is
=
+
2
2
y
x
v
v
s,
m
20
.
7
s)
m
43
.
4
(
s)
m
67
.
5
(
2
2
=

+
and his direction is arctan
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Unformatted text preview: ( 29 °=38 67 . 5 42 . 4 from the x axis, which is ° 1 . 91 from the direction of Rebecca’s final motion. b) 2 2 2 s) m (13.0 (45.0) 2 1 ) s m (7.195 kg) . 65 ( 2 1 s) m (8.0 kg) . 45 ( 2 1+ = ∆ K J. 680= Note that an extra figure was kept in the intermediate calculation....
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