problem08_43

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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8.43: a) In Eq. (8.24), let . and M m m m B A = = Solving for M gives A A v v v v m M + - = In this case, s, m 10 20 . 1 and s, m 10 50 . 1 7 7 × - = × = A v v with the minus sign indicating a rebound. Then, . 9 ) 20 . 1 ) 1.50 1.20 50 . 1 m m M = = - + + Either Eq. (8.25) may be used to find
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Unformatted text preview: s, m 10 00 . 3 6 5 × = = v B v or Eq. (8.23), which gives s), m 10 20 . 1 ( s) m 10 50 . 1 ( 7 7 ×-+ × = B v the same result....
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