problem08_55

University Physics with Modern Physics with Mastering Physics (11th Edition)

  • Homework Help
  • PresidentHackerCaribou10582
  • 1

Info icon This preview shows page 1. Sign up to view the full content.

8.55: a) The average thrust is the impulse divided by the time, so the ratio of the average thrust to the maximum thrust is . 442 . 0 s) (1.70 N) (13.3 s) N 0 . 10 ( = b) Using the average force in Eq.
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: (8.38), s. m 800 kg 0125 . s N . 10 ex = = = ⋅ dm dt F v c) Using the result of part (b) in Eq. (8.40), s m 530 ) 0133 . 0258 . ( ln ) s m 800 ( = = v ....
View Full Document

  • '
  • NoProfessor
  • Thrust, Ratio, Trigraph, average thrust

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern