problem08_67

University Physics with Modern Physics with Mastering Physics (11th Edition)

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8.67: a) The ratio of the kinetic energy of the Nash to that of the Packard is ( 29 ( 29 ( 29 ( 29 . 68 . 1 2 2 2 2 s m 5 kg 1620 s m 9 kg 840 = = P P N N v m v m b) The ratio of the momentum of the Nash to that of the Packard is 0.933, ) m/s kg)(5 1620 ( ) m/s kg)(9 (840 = = P P N N v m v m therefore the Packard has the greater magnitude of momentum. c) The force necessary to stop an object with momentum P in time t is F = / P - t . Since the Packard has the greater momentum, it will require the greater force
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Unformatted text preview: to stop it. The ratio is the same since the time is the same, therefore / = P N F F 0.933. d) By the work-kinetic energy theorem, = F d k ∆ . Therefore, since the Nash has the greater kinetic energy, it will require the greater force to stop it in a given distance. Since the distance is the same, the ratio of the forces is the same as that of the kinetic energies, / = P N F F 1.68....
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This document was uploaded on 02/04/2008.

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