problem08_71

University Physics with Modern Physics with Mastering Physics (11th Edition)

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8.71: a) Take the original direction of the bullet’s motion to be the x- direction, and the direction of recoil to be the y- direction. The components of the stone’s velocity after impact are then ( 29 , s m 0 . 21 s m 350 Kg 0.100 Kg 10 00 . 6 3 = × = - x v ( 29 , s m 0 . 15 s m 250 Kg 100 . 0 Kg 10 00 . 6 3 = × - = - y v and the stone’s speed is ( 29 ( 29 , s m 8 . 25 s m 0 . 15 s m 0 .
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Unformatted text preview: 21 2 2 = + at an angle of arctan ( 29 . 5 . 35 . 21 . 15 ° = b) ( 29 ( 29 J 368 m/s 350 kg 10 00 . 6 2 3 2 1 1 = × =-K ( 29 ( 29 2 3 2 1 2 m/s 250 kg 10 00 . 6-× = K ( 29 ( 29 , J 221 s / m 8 . 25 kg 100 . 2 2 2 1 = + so the collision is not perfectly elastic....
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