Exam-1_Student_S07_Sol

Exam-1_Student_S07_Sol - ECE 271 Exam-I Solutions Prof...

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ECE 271 Exam-I (02/26/2007) Solutions Prof. Hanafi (1) (15 points) Use voltage and current division to find V 1 , V 2 , I 2 , and I 3 in the circuit in Fig. (1) if V = 18 V, R 1 = 39 k Ω , R 2 = 43 k Ω , and R 3 = 11 k Ω . Figure (1) Solution. V = 18 V, R 1 = 39 k Ω , R 2 = 43 k Ω and R 3 = 11 k Ω . V + - V 1 V 2 + - R 1 R 2 R 3 I 3 I 2 V 1 = 18 V 39 k Ω 39 k Ω + 43 k Ω 11 k Ω ( ) = 14.7 V V 2 = 18 V 43 k Ω 11 k Ω 39 k Ω + 43 k Ω 11 k Ω ( ) = 3.30 V I 2 = I 1 11 k Ω 43 k Ω + 11 k Ω = 18 V 39 k Ω + 43 k Ω 11 k Ω ( ) 11 k Ω 43 k Ω + 11 k Ω = 76.7 μ A I 3 = I 1 43 k Ω 43 k Ω + 11 k Ω = 18 V 39 k Ω + 43 k Ω 11 k Ω ( ) 43 k Ω 43 k Ω + 11 k Ω = 0.300 mA
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