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problem08_77

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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8.77: a) The coefficient of friction, from either force or energy consideration, is , 2 2 k gs v μ = where v is the speed of the block after the bullet passes through. The speed of the block is determined from the momentum lost by the bullet, ( 29 ( 29 s, m kg 12 . 1 s m 280 kg 10 00 . 4 3 = × - and so the coefficient of kinetic friction is ( 29 ( 29 ( 29 ( 29 . 22 . 0 m 45 . 0 s m 80
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Unformatted text preview: . 9 2 ) kg 80 . ( s m kg 12 . 1 2 2 k = ⋅ = μ b) ( 29 ( 29 ( 29 ( 29 J. 291 s m 120 s m 400 kg 10 00 . 4 2 2 3 2 1 =-×-c) From the calculation of the momentum in part (a), the block’s initial kinetic energy was . J 784 . kg) 80 . ( 2 ) s m kg 12 . 1 ( 2 2 2 = = ⋅ m p...
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