problem08_77

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
8.77: a) The coefficient of friction, from either force or energy consideration, is , 2 2 k gs v μ = where v is the speed of the block after the bullet passes through. The speed of the block is determined from the momentum lost by the bullet, ( 29 ( 29 s, m kg 12 . 1 s m 280 kg 10 00 . 4 3 = × - and so the coefficient of kinetic friction is ( 29 ( 29 ( 29 ( 29 . 22 . 0 m 45 . 0 s m 80
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: . 9 2 ) kg 80 . ( s m kg 12 . 1 2 2 k = ⋅ = μ b) ( 29 ( 29 ( 29 ( 29 J. 291 s m 120 s m 400 kg 10 00 . 4 2 2 3 2 1 =-×-c) From the calculation of the momentum in part (a), the block’s initial kinetic energy was . J 784 . kg) 80 . ( 2 ) s m kg 12 . 1 ( 2 2 2 = = ⋅ m p...
View Full Document

This document was uploaded on 02/04/2008.

Ask a homework question - tutors are online