problem08_79

University Physics with Modern Physics with Mastering Physics (11th Edition)

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8.79: a ) Using the notation of Eq. ( 8.24 ), . ) ( 4 ) ( ) ( ) ( 1 2 1 2 1 2 1 2 0 2 2 2 0 2 2 2 2 2 0 + = + - - + = + - - = - = - M m mM K M m M m M m K M m M m mv mv mv K K A b) Of the many ways to do this calculation, the most direct way is to differentiate the expression of part (a) with respect to M and set equal to zero;
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Unformatted text preview: . 2 ) ( ) ( 2 ) ( 1 or , ) ( ) K 4 ( 3 2 2 M m M M m M m M M m M m M dM d m =-+ = +-+ = + = c) From Eq.(8.24), with 0; , = = = A B A v m m m the neutron has lost all of its kinetic energy....
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This document was uploaded on 02/04/2008.

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