University Physics with Modern Physics with Mastering Physics (11th Edition)

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8.80: a) From the derivation in Sec. 8.4 of the text we have B A A B 0 B A B A A 2 and M M M V V M M M M V + = + - = The ratio of the kinetic energies of the two particles after the collision is B A 2 B A B A B A 2 B A 2 A B A B A 2 B A B A 2 B B 2 1 2 A A 2 1 4 ) ( or 4 ) ( 2 M M M M KE KE M M M M M M M M M V V M M V M V M - = - = - = = b) i) For ; 0 , A B A = = KE M M i.e., the two objects simply exchange kinetic energies. ii) , 5 For B A M M = 5 4 ) )( 5 ( 4 ) 4 ( B B 2 B B A = = M M M KE KE i.e., A M gets 4/9 or 44% of the total.
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Unformatted text preview: c) We want B A 2 B B A 2 A B A 2 B A B A 4 2 4 ) ( 1 M M M M M M M M M M KE KE +-=-= = which reduces to , 6 2 B B A 2 A = +-M M M M from which, using the quadratic formula, we get the two possibilities B A 83 . 5 M M = and B. A 172 . M M =...
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  • Kinetic Energy, Ratio, AVA M, KE B 4M, 2M A 4M, MB 2M

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