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8.85:
a) If the crate had final speed
v
, J&J have speed 4.00
v

s
m
relative to the ice,
and so
).
m/s
kg)(4.00
20.0
1
(
kg)
0
.
15
(
v
v

=
Solving for
.
s
m
56
.
3
,
kg)
0
.
135
(
s)
m
(4.00
kg)
0
.
120
(
=
=
v
v
b) After Jack jumps, the speed of the crate is
,
s
m
222
.
2
)
s
m
00
.
4
(
kg)
(135.0
kg)
0
.
75
(
=
and the
momentum of Jill and the crate is
s
m
kg
3
.
133
⋅
. After Jill jumps, the crate has a speed
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Unformatted text preview: v and Jill has speed 4.00 , s m vand so = ⋅ v ) kg . 15 ( s m kg 3 . 133 ), s m 00 . 4 kg)( . 45 ( vand solving for v gives s. m 22 . 5 = v c) Repeating the calculation for part (b) with Jill jumping first gives a final speed of s. m 67 . 4...
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