problem08_85

University Physics with Modern Physics with Mastering Physics (11th Edition)

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8.85: a) If the crate had final speed v , J&J have speed 4.00 v - s m relative to the ice, and so ). m/s kg)(4.00 20.0 1 ( kg) 0 . 15 ( v v - = Solving for . s m 56 . 3 , kg) 0 . 135 ( s) m (4.00 kg) 0 . 120 ( = = v v b) After Jack jumps, the speed of the crate is , s m 222 . 2 ) s m 00 . 4 ( kg) (135.0 kg) 0 . 75 ( = and the momentum of Jill and the crate is s m kg 3 . 133 . After Jill jumps, the crate has a speed
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Unformatted text preview: v and Jill has speed 4.00 , s m v-and so -= ⋅ v ) kg . 15 ( s m kg 3 . 133 ), s m 00 . 4 kg)( . 45 ( v-and solving for v gives s. m 22 . 5 = v c) Repeating the calculation for part (b) with Jill jumping first gives a final speed of s. m 67 . 4...
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This document was uploaded on 02/04/2008.

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