U210_sol03 - An error of 1% of full scale means v(x) =...

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ECEU210 Solutions to HW #3 P 10.1 P 10.2
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P 10.3 P 10.4 Refer to Figure P10.4 on page 562. The Thevenin equivalent circuit for the potentiometer is V T = V oc = xV R eq = xR p || (1-x)R p = x(1-x) R p 2 / [xR p + (1-x) R p ] = x(1-x)R p A load R L will reduce the voltage to v(x) = V oc * R L / (R eq + R L ) = xV /( R eq / R L + 1)
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Unformatted text preview: An error of 1% of full scale means v(x) = (x-0.01)V xV /( R eq / R L + 1) = (x-0.01)V R eq / R L + 1 = x/(x-0.01) R eq / R L = x/(x-0.01) - 1 The highest value of R eq occurs for x=0.5, (R eq ) max = R p /4 R p /4R L = 0.5/0.49 1 = 0.0204 R L / R p = 12.3...
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This note was uploaded on 04/07/2008 for the course ECE U210 taught by Professor Shekel during the Spring '08 term at Northeastern.

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U210_sol03 - An error of 1% of full scale means v(x) =...

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