0 g v3 v3 t3 t2 pdt w t3 t2 mv3 43 2 4 v3 g 3 10dt 2

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Unformatted text preview: 2) 4 v3 g 3 10dt 2 (32.2 ft/s 2 ) [(6 lb)(1 s)] v3 (4 lb) 29.0 48.3 77.3 ft/s (29.0 ft/s) Chapter 13, Solution 156 (a) mA e mB m 0 Conservation of total momentum. mv A (b) mvB v 2mv Energy loss. EL TA TB (TA TB ) EL 1 2 m vA 2 2 vB 1 m (v 2 2 v 2) From (a), v EL EL EL 1 (v A 2 vB ) 1 1 1 2 2 m v A vB m (v A v B ) 2 2 2 2 1 1 2 2 2 2 m v A vB m v A 2v A vB vB 2 4 1 2 2 m v A 2v A vB vB 4 1 m (v A vB ) 2 4 1 (v A 2 vB ) Chapter 13, Solution 173 Directions x, y, n, and t are shown in the sketch. Analysis of the impact. Use the principle of impulse and momentum for componen...
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