**Unformatted text preview: **and equation first in the B A v v m/s. 3 . 14 ) ( Then m/s. 6 . 71 and J 860 ) / 1 ( 2 2 1 = = = = + B A B A B A B B B v m m v v m m v m b) Use the vertical motion from the maximum height to the ground to find the time it takes the pieces to fall to the ground after the explosion. Take + y downward. s. 4.04 t gives ? m, . 80 , m/s 80 . 9 , 2 2 1 2 = + =-= =-+ = = t a t v y y t y y a v y y y y During this time the horizontal distance each piece moves is m. 1 . 289 and m 8 . 57 = = = = t v x t v x B B A A They move in opposite directions, so they are m 347 = + B A x x apart when they land....

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