This preview shows page 1. Sign up to view the full content.
8.99:
The information is not sufficient to use conservation of energy. Denote the emitted
neutron that moves in the

y
+
direction by the subscript 1 and the emitted neutron that
moves in the –
y
direction by the subscript 2. Using conservation of momentum in the
x
and
y
directions, neglecting the common factor of the mass of neutron,
.
30
sin
45
sin
10
)sin
3
2
(
0
30
cos
45
cos
10
cos
)
3
2
(
2
1
0
2
1
0
0
°

°
+
°
=
°
+
°
+
°
=
v
v
v
v
v
v
v
With
°
=
°
45
cos
45
sin
, these two relations may be subtracted to eliminate
,
1
v
and
rearrangement gives
This is the end of the preview. Sign up
to
access the rest of the document.
Unformatted text preview: ), 30 sin 30 cos ( ) 10 )sin 3 2 ( 10 cos ) 3 2 ( 1 ( 2 ° + ° = ° + °v v from which 2 v s m 10 1.0 or s m 10 01 . 1 3 3 × × = to two figures. Substitution of this into either of the momentum relations gives s. m 221 1 = v All that is known is that there is no z component of momentum, and so only the ratio of the speeds can be determined. The ratio is the inverse of the ratio of the masses, so Ba Kr ) 5 . 1 ( v v = ....
View
Full
Document