problem08_p102

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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8.102: a) The decrease in potential energy ( 29 0 < - means that the kinetic energy increases. In the center of mass frame of two hydrogen atoms, the net momentum is necessarily zero and after the atoms combine and have a common velocity, that velocity must have zero magnitude, a situation precluded by the necessarily positive kinetic energy. b) The initial momentum is zero before the collision, and must be zero after the collision. Denote the common initial speed as 0 v , the final speed of the hydrogen atom as v , the final speed of the hydrogen molecule as
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Unformatted text preview: V , the common mass of the hydrogen atoms as m and the mass of the hydrogen molecules as 2 m . After the collision, the two particles must be moving in opposite directions, and so to conserve momentum, V v 2 = . From conservation of energy, ( 29 2 2 1 2 2 3 2 1 2 2 1 mv mv V m = + ∆-2 2 3 2 2 2 mv mV mV = + ∆-m v V 3 2 2 2 ∆ + = , from which m/s, 10 203 . 1 4 × = V or 1.20 × 4 10 m/s to two figures and the hydrogen atom speed is 4 10 2.41 × = v m/s....
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## This document was uploaded on 02/04/2008.

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