problem08_p105

University Physics with Modern Physics with Mastering Physics (11th Edition)

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8.105: a) From Eq. ( 29 ( 29 ( 29 . 37 . 1 ln , 40 . 8 ex kg 3,300 kg 13,000 ex v v v = = b) ( 29 ( 29 . 1.18 000 , 4 / 000 , 13 ln ex ex v v = c) ( 29 ( 29 ( 29 . 38 . 2 300 / 1000 In 18 . 1 ex ex ex v v v = + d) Setting the result of part (c) equal to
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Unformatted text preview: 7.00 km/s and solving for ex v gives . km/s 94 . 2 ex = v...
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