problem08_p112

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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8.112: a) For constant acceleration a , the downward velocity is = v at and the distance x that the drop has fallen is . 2 2 1 at x = Substitution into the differential equation gives ( 29 2 2 2 2 2 2 3 2 1 2 1 t a at a at g at = + = , the non-zero solution of which is
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Unformatted text preview: . 3 g a = b) ( 29 . m 7 . 14 s 00 . 3 3 m/s 9.80 2 1 2 1 2 2 2 = = at c) ( 29 ( 29 . g 4 . 29 m 7 . 14 g/m 00 . 2 = = kx...
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