Chapter 18, Lecture 1

Chapter 18, Lecture 1 - MnO 4-1 + S 2 O 3-2 Mn +2 + SO 4-2...

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CH18-LECT1 Page 1 CHAPTER 18 ELECTROCHEMISTRY CHEM REACTIONS ELECTRICITY REDOX REACTIONS RED UCTION OX IDATION REDOX REACTIONS INVOLVE AN ELECTRON TRANSFER EVERY REDOX REACTION CONSISTS OF TWO HALF REACTIONS: 1. AN OXIDATION HALF-REACTION A LOSS OF ELECTRONS (LEO) 2. A REDUCTION HALF-REACTION A GAIN OF ELECTRONS
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CH18-LECT1 Page 2 HALF-REACTION METHOD TO BALANCE REDOX REACTIONS Separate into a pair of half-reactions Balance each reaction with respect to mass (# atoms of each element the same) Balance each with respect to charge by adding electrons Adjust coefficients so that #e lost = #e gained Add the two half-reactions Simplify
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CH18-LECT1 Page 3 EX 18.1 Balance this equation: MnO 4 -1 is an oxidizing agent; thiosulfate ion, S 2 O 3 -2 , is used as a reducing agent. Balance the equation for the reaction of these ions in acidic aqueous solution.
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Unformatted text preview: MnO 4-1 + S 2 O 3-2 Mn +2 + SO 4-2 Reduction: MnO 4-1 Mn +2 MnO 4-1 + 8 H + Mn +2 + 4 H 2 O Mass OK 5 e-+ MnO 4-+ 8 H + Mn +2 + 4 H 2 O Mass & Charge OK Oxidation: S 2 O 3-2 + 5 H 2 O 2 SO 4-2 S 2 O 3-2 + 5 H 2 O 2 SO 4-2 + 10 H + Mass OK S 2 O 3-2 + 5 H 2 O 2 SO 4-2 + 10 H + + 8 e-Mass & Charge OK Adjust coefficients so that #e lost = # e gained Reduction: 8 MnO 4-1 + 64 H + + 40 e-1 8 Mn +2 + 32 H 2 O Oxidation: 5 S 2 O 3-2 + 25 H 2 O 10 SO 4-2 + 50 H + + 40 e-1 Combine: 8 MnO 4-1 + 5 S 2 O 3-2 + 14 H + 8 Mn +2 + 10 SO 4-2 + 7 H 2 O CH18-LECT1 Page 4 VOLTAIC CELL Uses an oxidation-reduction reaction to produce electrical current CH18-LECT1 Page 5 FIG. 17.11 Direction & Extent of Spontaneous Change CH18-LECT1 Page 6 CH18-LECT1 Page 7...
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Chapter 18, Lecture 1 - MnO 4-1 + S 2 O 3-2 Mn +2 + SO 4-2...

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