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Chapter 19, lecture 2

Chapter 19, lecture 2 - 4.0320 u 4.0015 u NUCLEAR FISSION A...

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CHAPTER 19 NUCLEAR CHEMISTRY Page 1 SYNTHETIC NUCLIDES Ruhterford - 1919 TRANSURANIUM ELEMENTS
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CHAPTER 19 NUCLEAR CHEMISTRY Page 2 EINSTEIN’S EQUATION: E = mc 2 Example 19.8 Given the nuclear masses: 241 95 Am = 241.0046 u 237 93 Np = 236.997 u 4 2 He = 4.0015 u Calculate the energy associated with the α decay of Americanium-241 in MeV. 241 95 Am 237 93 Np + 4 2 He 241.0046 u 236.9970 u 4.0015 u 236.9970 u + 4.0015 u - 241.0046 u = - 0.0061 u Energy = - 0.0061 u x (931.5 MeV / 1 u ) = - 5.7 MeV
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CHAPTER 19 NUCLEAR CHEMISTRY Page 3 Figure 19.6 Nuclear Binding Energy of the α particle 1.0073 u p 1.0073 u p P P n n 1.0087 u n 1.0087 u n Δ = - 0.0305 u
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Unformatted text preview: _______ __________ 4.0320 u 4.0015 u NUCLEAR FISSION A heavy nucleus splitting into lighter ones NUCLEAR FUSION Light nuclei combining to form heavier nuclei CHAPTER 19 NUCLEAR CHEMISTRY Page 4 CHAPTER 19 NUCLEAR CHEMISTRY Page 5 FIG. 19.9 A NUCLEAR POWER PLANT FUSION REACTIONS CHAPTER 19 NUCLEAR CHEMISTRY Page 6 CHAPTER 19 NUCLEAR CHEMISTRY Page 7 ORGANIC REACTION MECHANISM STUDIES Ester hydrolysis: Use of 18 O labeled water allows the mechanism to be deduced. Actually the bond between the Carbonyl group (C=O) and the O is the one that cleaves in the hydrolysis....
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