18 Casing Design Example

# Compare with previous depth estimate 6 repeat steps 2

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Unformatted text preview: stance 4. Determine depth where this pressure exists 5. Compare with previous depth estimate 6. Repeat steps 2-6 using the new depth estimate 7. When depths agree, accept answer (typically 2-4 iterations) (agreement to within 30 ft will be satisfactory) 38 Linear Interpolation y = mx + c P = mS + C (i) P1 = mS 1 + C (ii) P 2 = mS 2 + C (iii) 39 Linear Interpolation (iii) − (ii) (i) − (ii) P2 − P1 = m(S2 − S1 ) ⇒ P2 − P 1 m= S2 − S1 P2 − P 1 (S − S1 ) P − P = m(S − S1 ) = 1 S −S 2 1 40 Linear Interpolation S − S1 ∴ P = P1 + S − S (P2 − P1 ) 1 2 With design factor: S − S1 1 Pcc = P1 − S − S (P1 − P2 ) D.F. 1 2 41 42 43...
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## This note was uploaded on 12/03/2012 for the course PMRE PMRE6004 taught by Professor M.tamim during the Summer '12 term at Bangladesh University of Eng and Tech.

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