problem09_19

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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9.19: a) Before the circuit breaker trips, the angle through which the wheel turned was 108 2 s) (2.00 ) s rad (30.0 s) (2.00 ) s rad 0 . 24 ( 2 2 = + rad, so the total angle is rad. 540 rad 432 rad 108 = + b) The angular velocity when the circuit breaker trips is ( 29 ( 29 ( 29 s, rad 84 s 00 . 2 s rad 0 . 30 s rad 0 . 24 2 = + so the average angular velocity while the wheel is slowing is s, rad 0 . 42 and the time to slow to a stop is
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Unformatted text preview: s, 3 . 10 s rad 42.0 rad 432 = so the time when the wheel stops is s 3 . 12 . c) Of the many ways to find the angular acceleration, the most direct is to use the intermediate calculation of part (b) to find that while slowing down = ∆ z ω s rad 84-so . s rad 17 . 8 2 s 3 . 10 s rad 84-= = α-z...
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