This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Understanding Lenses Description: Includes Math Remediation. Qualitative and quantitative questions about image formation by lenses. Learning Goal: To learn the quantitative use of the lens equation, as well as how to determine qualitative properties of solutions. In working with lenses, there are three important quantities to consider: The object distance is the distance along the axis of the lens to the object. The image distance is the distance along the axis of the lens to the image. The focal length is an intrinsic property of the lens. These three quantities are related through the equation . Note that this equation is valid only for thin, spherical lenses. Unless otherwise specified, a lens problem always assumes that you are using thin, spherical lenses. The equation above allows you to calculate the locations of images and objects. Frequently, you will also be interested in the size of the image or object, particularly if you are considering a magnifying glass or microscope. The ratio of the size of an image to the size of the object is called the magnification . It is given by , where is the height of the image and is the height of the object. The second equality allows you to find the size of the image (or object) with the information provided by the thin lens equation. All of the quantities in the above equations can take both positive and negative values. Positive distances correspond to real images or objects, while negative distances correspond to virtual images or objects. Positive heights correspond to upright images or objects, while negative heights correspond to inverted images or objects. The following table summarizes these properties: real virtual real virtual upright inverted upright inverted The focal length can also be positive or negative. A positive focal length corresponds to a converging lens, while a negative focal length corresponds to a diverging lens. Consider an object with that produces an image with . Note that whenever you are working with a physical object, the object distance will be positive (in multiple optics setups, you will encounter "objects" that are actually images, but that is not a possibility in this problem). A positive image distance means that the image is formed on the side of the lens from which the light emerges. Part A Find the focal length of the lens that produces the image described in the problem introduction using the thin lens equation. Express your answer in centimeters, as a fraction or to three significant figures. ANSWER: = Part B Considering the sign of , is the lens converging or diverging? ANSWER: converging diverging Part C What is the magnification of the lens? Express your answer as a fraction or to three significant figures....
View Full
Document
 Summer '08
 Geller

Click to edit the document details