problem09_77

University Physics with Modern Physics with Mastering Physics (11th Edition)

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Unformatted text preview: 9.77: a) = 90.0 rpm = 9.425 rad s 1 2 K 2( 10.0 106 J) K = 2 so = 2 = = 2.252 105 kg m 2 2 ( 9.425 rad s) 2 m = V = R 2t ( = 7800 kg m 3 is the density of iron and t=0.100 m is the thickness of the flywheel) 1 1 = mR 2 = tR 4 2 2 R = ( 2 I t )1 4 = 3.68 m; diameter = 7.36 m b) ac = R2 = 327 m s 2 ...
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This document was uploaded on 02/04/2008.

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