problem09_83

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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9.83: a) ( 29 ( 29 ( 29 J. 784 . 0 s m 80 . 9 m 500 . 0 kg 160 . 0 2 - = - b) The kinetic energy of the stick is 0.784 J, and so the angular velocity is ( 29 ( 29 . s rad 42 . 5 3 m . 1 00 kg 160 . 0 J) ( . 2 0 784 3 2 2 2 2 = = = = ML k I k ϖ This result may also be found by using the algebraic form for the kinetic energy, , 2 MgL K = from which
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Unformatted text preview: , 3 L g = giving the same result. Note that ω is independent of the mass. ( 29 ( 29 s m . 5 42 m . 1 00 s rad 42 . 5 c) = = = L v (c). part of result the of 3 2 is This ; s m 43 . 4 g 2 d) = L...
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