**Unformatted text preview: **9.91: We can use (cylinder) = 250 J to find for the cylinder and v for the mass. = 1 MR 2 = 1 (10.0 kg)(0.150 m)2 = 0.1125 kg m 2 2 2 K = 1 I2 so = 2 K I = 66.67 rad s 2 v = R = 10.0 m s Use conservation of energy K 1 + U 1 = K 2 + U 2 . Take y = 0 at lowest point of the mass, so y 2 = 0 and y1 = h, the distance the mass descends. K1 = U 2 = 0 so U1 = K 2 . mgh = 1 mv 2 + 1 I 2 , where m = 12.0 kg 2 2
2 For the cylinder, I = 1 MR and = v R , so 2 1 2 I 2 = 1 Mv 2 . 4 mgh = 1 mv 2 + 1 Mv 2 2 4 h= v2 M 1 + = 7.23 m 2 g 2m ...

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