problem09_p100

University Physics with Modern Physics with Mastering Physics (11th Edition)

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9.100: Following the procedure used in Example 9.14 (and using z as the coordinate along the vertical axis) Then, . and 4 2 2 4 4 2 2 dz z dz z πρ dm , z r(z) h R πρ h R h R = = = [ ] . h πρR z h R πρ dz z h R πρ Ι h h = = = = 0 4 0 5 4 4 4 4 10 1 10 2 The volume of a right circular cone is
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Unformatted text preview: so and is mass the , 2 3 1 2 3 1 h R h R V π = . 10 3 3 10 3 2 2 2 ΜR R h R π Ι = ρ =...
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  • Cone, right circular cone, R4 z dz

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