MECH 213 - 10.9.07

MECH 213 - 10.9.07 - MECH 213 October 9, 2007 q w = du Tds...

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MECH 213 – October 9, 2007 δq – δw = du Tds – pdv = du Tds = du + pdv o dh = du + pdv +vdp o dh – vdp = du + pdv o Tds = dh – vdp Incompressible o ds = du/T o S1 S2 ds = ∫ T1 T2 cdT/T o s 2 – s 1 = c*ln(T 2 /T 1 ) Ideal Gases o pv = RT o dh = c p dT o du = c v dT o c p – c v = R o c p /c v = k ds = du/T + (p/T)dv S1 S2 ds = ∫ T1 T2 c v dT/T + ∫ v1 v2 (R/v)dv if c v = constant o **Δs = c v *ln(T 2 /T 1 ) + R*ln(v 2 /v 1 ) Δs = ∫ S1 S2 ds = ∫ T1 T2 c p dT/T – R*ln(p 2 /p 1 ) If c p = constant o Δs = c p *ln(T 2 /T 1 ) – R*ln(p 2 /p 1 ) Δs = ∫ 0 T2 c p dT/T – ∫ 0 T1 c p dT/T – R*ln(p 2 /p 1 ) o Δs = S 0 (T 2 ) – S 0 (T 1 ) – R*ln(p

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This note was uploaded on 04/07/2008 for the course MECH 213 taught by Professor Knisley during the Spring '08 term at Bucknell.

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MECH 213 - 10.9.07 - MECH 213 October 9, 2007 q w = du Tds...

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