MECH 213 - 10.1.07

MECH 213 - 10.1.07 - MECH 213 October 1, 2007 Q W = mu q w...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
MECH 213 – October 1, 2007 ΣθΔ ρ Q – W = mΔu q – w = Δu Steady State, open System o Qdot – Wdot = Σ(mdot*θ) out – Σ(mdot*θ) in o 0 = Δh + Δke o Assume adiabatic o –Wdot = mdot(Δh + Δke) o If non-adiabatic Qdot – Wdot = mdot(Δh + Δke) o Assume incompressible Δh = Δu + pΔv + vΔp = Δu + vΔp o Isentropic Δu 0 Δh = vΔp -Wdot = mdot(Δp/ρ) Throttling Device o Δh = 0 o Δu + Δpv = 0 o u 1 + p 1 v 1 = u 2 + p 2 v 2 o 0 = Σ(mdot*h) out – Σ(mdot*h) in Piping o Pipe flow 0 = Δh + Δke + Δpe o incompressible, Δv
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 2

MECH 213 - 10.1.07 - MECH 213 October 1, 2007 Q W = mu q w...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online