MECH 213 - 9.28.07

MECH 213 - 9.28.07 - Qdot b,Act = mdot b c pb (T b2 – T...

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MECH 213 – September 28, 2007 Heat exchangers (HX) What it is o a pipe surrounded by a pipe o two distinct fluids that do not mix First Law o If the system includes both pipes Qdot – Wdot = Σ(mdot*θ) out – Σ(mdot*θ) in Fluid A = mdot a Fluid B = mdot b Δke ≈ 0 Δpe ≈ 0 0 = Σ(mdot*h) out – Σ(mdot*h) in 0 = (mdot a *h a2 + mdot b *h b2 ) – (mdot a *h a1 + mdot b *h b1 ) 0 = mdot a (h a2 – h a1 ) + mdot b (h b2 – h b1 ) o Also called enthalpy balance o System A only Qdot a = mdot a (h a2 – h a1 ) o System B only Qdot b = mdot b (h b2 – h b1 ) o -Qdot a = Qdot b o Δh = c p ΔT 0 = mdot a c pa (T a2 – T a1 ) + mdot b c pb (T b2 – T b1 ) if the fluids have equal mdot*c p the temperature gain in one is the same as the loss in the other thermal capacity = mdot*c p o Regenerator – heat exchanger that reuses waste heat o Effectiveness – determines how well a heat exchanger operates (not in text) ε ≡ Qdot ACTUAL /Qdot MAX must be between 0 and 1 will be the same for both fluids
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Unformatted text preview: Qdot b,Act = mdot b c pb (T b2 – T b1 ) Qdot b,Max = mdot b c pb (T a1 – T b1 ) Mixing Chamber (MX) o Does exactly the same thing as a heat exchanger except that the two fluids leave the same outlet at the same temperature o Example – faucet (hot & cold water) o 0 = (mdot A + mdot B )h 2 – mdot a h a1 – mdot b h b1 o B A A mdot A + mdot b B Tubing and piping o Tubing – cylinder inside an object Usually very thick to prevent breaking o Piping – cylinder that connects an object externally to something else 1 2 Pipe Qdot – Wdot = mdot(Δh + Δke + Δpe) 0 = mdot(h 2 – h 1 + (V 2 2 – V 1 2 )/2 + g(z 2 – z 1 ) 0 = (p 2 – p 1 )/ρ + (V 2 2 – V 1 2 )/2 + g(z 2 – z 1 ) Bernoulli’s Principle p 1 /ρ + V 1 2 /2 + gz 1 = p 2 /ρ + V 2 2 /2 + gz 2...
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This note was uploaded on 04/07/2008 for the course MECH 213 taught by Professor Knisley during the Fall '08 term at Bucknell.

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MECH 213 - 9.28.07 - Qdot b,Act = mdot b c pb (T b2 – T...

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