MECH 213 - 9.24.07

MECH 213 - 9.24.07 - MECH 213 September 24, 2007 QUIZ...

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MECH 213 – September 24, 2007 QUIZ TOMORROW!!! – up through this material m in – m out = Δm sys -(m out – m in ) = Δm sys Rate: o -(m out dot – m in dot) = Δm sys /Δt o ∫∫ cs ρ(V•n)dA d/dt(∫∫∫ cv ρdV) Steady flow – nothing changes over time (d/dt = 0) o Σm in dot = Σm out dot o Single inlet/outlet m in dot = m out dot = ρ 1 A 1 V 1 = ρ 2 A 2 V 2 First Law o Q net.in – W net.out + Σm in (p/ρ + u + ke + pe) in – Σm out (p/ρ + u + ke + pe) out = ΔE = m sys (u + ke + pe) sys o Q net.in dot – W net.out dot + Σm in dot(p/ρ + u + ke + pe) in – Σm out dot(p/ρ + u + ke + pe) out = ΔE/Δt = [m sys dot(u + ke + pe) sys ]/Δt In a steady state the right side disappears o Energy of a flowing fluid = θ ≡ h + ke + pe Steady State o ΔE/Δt 0 o Q net.in dot – W net.out dot = –Σm in dot(p/ρ + u + ke + pe) in + Σm out dot(p/ρ + u + ke + pe) out o Q net.in dot – W net.out dot = –Σm in dot(θ) in + Σm out dot(θ) out o Single inlet/outlet m in dot = m out dot = mdot Q net.in dot – W net.out dot = mdot(θ out – θ in ) Divide both sides by mdot q net.in
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MECH 213 - 9.24.07 - MECH 213 September 24, 2007 QUIZ...

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