This preview shows page 1. Sign up to view the full content.
Unformatted text preview: If X is continuous: F(x) =  x f(t)dt Find the cdf for the variable in problem 26 o F(y) = P(Y y) = { 0 for y 0 } { y (3/14)(t + t 2 )dt for 0 < y < 2 } { 1 for y 2 } o F(y) = P(Y y) = { 0 for y 0 } { (3y 2 + 2y 3 )/28 for 0 < y < 2 } { 1 for y 2 } The expected value of a continuous random variable is o EX =  xf(x)dx The variance is o Var(x) =  (x ) 2 f(x)dx = EX 2 (EX) 2 Example 24 o A. Mean = Var(x) = 1/(2*sqrt(3)) = .289 o B. o C. 1  .995 = .005...
View
Full
Document
This note was uploaded on 04/07/2008 for the course MATH 226 taught by Professor Daepp during the Fall '07 term at Bucknell.
 Fall '07
 Daepp
 Math, Probability

Click to edit the document details