Unformatted text preview: b j = ybar •j ybar •• a 1 = 4.78 – 4.99 = 0.21 a 2 = 5.68 – 4.99 = 0.69 a 3 = 4.50 – 4.99 = 0.49 a i = ybar i• ybar •• ybar ij ≈ ybar •• + a i + b j to finish the definition The fitted interaction between level i of Factor A and level j of factor B is ab ij = ybar ij – (ybar •• + a i + b j ) ybar ij ≈ ybar •• + a i + b j + ab ij R 2 = [Σ(y – ybar) 2 – Σ(yhat – y) 2 ]/ Σ(y – ybar) 2 y ij ≈ μ + α i + β j + αβ ij yhat ij = ybar •• + a i + b j + ab ij y ij ≈ μ + α i + β j yhat ij = ybar •• + a i + b j...
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This note was uploaded on 04/07/2008 for the course MATH 226 taught by Professor Daepp during the Fall '07 term at Bucknell.
 Fall '07
 Daepp
 Math

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