025 input voltage figure 4 shows the raw data

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: otted the current as a function of the voltage in Figure 1 to get an experimental value for 1/R from the slope of a linear regression. As can be seen on the graph, our slope was m = 0.001 (m = 0.00007 and b = 0.00001 from Excel) and taking the inverse of that gave us an experimental resistance of 1000 ohms. Our resistance data is summarized below. Table 6: Shows the experimental resistance and its actual measured resistance. Rexp (ohms) 1000 0.00007 Next, I analyzed our diode circuit in order to find an experimental ratio between e/kB which we could compare to the theoretical ratio. First, I calculated the theoretical ratio, which is summarized in Table 7. I calculated current data by Rmeasured (ohms) 993 0.05 R 7 R % 1.41 dividing the voltage data collected for r by our measured resistance of r. I then linearized the current data and plotted it against the voltage data in Figure 2, which allowed us to use a linear regression to find the experimental ratio. The slope of that regression can be seen in Figure 2 to be m = 20.602 (m = 0.04074 and b = 0.02745 from Excel), which when multiplied by n*T yields a ratio of 12072.8. All of the data is summarized in the table below. Table 7: Summarizes the theoretical and experimental ratios between e and kB. e (C) kB (J/K) e/kB_th r (ohms) n 1.6022E-19 1.3806E-23 11604.9 99.2 2 T (K) e/kB_exp ratio 293 12072.8 467.9 ratio % 3.95 In the AC portion of the lab, we were allowed to choose either the RC or the RL data to analyze and find the experimental time constant for the circuit. I chose to analyze the RC circuit. Again, we had to linearize the voltage data in order to take an approximate a linear regression. That data is plotted below in Figure 6 and resulted in a regression slope of m = -923.81 (m = 11.2747 and b = 0.04183 from Excel). Taking the inverse of this slope gave us an experimental time constant of 0.00108. Voltage (Linearized) vs Time 2 1.5 ln(Vb - V) (v) 1 0.5 0 -0.5 -1 -1.5 -2 Time (s) 0 0.002 0.004 0.006 0.008 trans time Linear (trans time) y = -923.81x + 4.9302 Figure 6: Shows a linearized plot of Voltage vs Time for the...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online