problem10_23

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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10.23: ) 1 eq. ( ) cos (sin cos sin cos s s a θ μ θ g ma θ mg μ θ mg mg n = - = - α = n and mg act at the center of the ball and provide no torque. α mR θ mg μ τ mR I θR mg μ τ τ f 2 5 2 s 2 5 2 s cos gives ; cos = = = = = No slipping means (eq.2) cos so , 5 2 s a g μ R a α = θ = We have two equations in the two unknowns a and . s μ Solving gives 613 . 0 0 . 65 tan tan and sin 7 2 7 2 7 5 = ° = = = θ μ θ g a s b) Repeat the calculation of part (a), but now

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• The Hollow, mg cos

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