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Unformatted text preview: a) 1.8 .6 .4 .2 0 .2 .4 .6 .8 1642 2 4 6 time (s) amplitude (V) amplitude vs. time y = 3cos(400*pi*t ) y = 6cos(200*pi*t + pi/4) b) Assuming CH1 = X and CH2 = Y, the Lissajous figure is: 321 1 2 3642 2 4 6 3. a) 5 10 15 20 25 30 35 40 45 50 5 10 15 20 25 30 35 40 45 50 number of returns height (cm) height vs. number of returns This relationship is given by the function H = 50*e0.05i b) (.409)(mgh) = 2.0041 J [assume mass is 1 kg] the corresponding height for this energy would be 2.0041 J /9.8 m/s 2 = 20.45 cm 20.45 = 50*e0.05i .409 = e0.05i ln(.409) = 0.05i i = 18 returns...
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This note was uploaded on 04/07/2008 for the course PHYS 122L taught by Professor Gougousi during the Spring '07 term at UMBC.
 Spring '07
 Gougousi
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