# Southern New Hampshire University - 4-2 Problem Set_ Module Four.pdf

• 17
• 83% (6) 5 out of 6 people found this document helpful

This preview shows page 1 - 5 out of 17 pages.

[PRINT]MAT-136-T2129 20EW2 Intro to Quantitative Analysis, 4-2 Problem Set: Module Four Angie Mann, 11/29/20 at 7:57:26 PM ESTQuestion1:Score 0/5Given f(x) =x2+ 9xand g(x) = 1 −x2, find f+g, fg, fg, and fg. Enclose numerators and denominators in parentheses. For example, (ab)/(1 +n).(f+g)(x) = Your responseCorrect responseNo answer9*x+1Auto gradedGrade:0/1.0 F 0% (fg)(x) = Your responseCorrect responseNo answer2*x^2+9*x-1Auto gradedGrade:0/1.0 F 0% fg(x) = Your responseCorrect responseNo answer-x^4-9*x^3+x^2+9*xAuto gradedGrade:0/1.0 F 0% fg(x) = Your responseCorrect responseNo answer(x^2+9*x)/(1-x^2)Auto gradedGrade:0/1.0 F 0% Total grade:0.0×1/4 + 0.0×1/4 + 0.0×1/4 + 0.0×1/4 = 0% + 0% + 0% + 0%Feedback:f+g=x2+ 9x+1 −x2= 9x+ 1()()
Since both f(x) and g(x) have domains of (−∞,∞), the domain of f+gis (−∞,∞).fg=x2+ 9x1 −x2= 2x2+ 9x− 1Since both f(x) and g(x) have domains of (−∞,∞), the domain of fgis (−∞,∞).fg=x2+ 9x1 −x2= 1x2x4+ 9x− 9x3= −x4− 9x3+ 1x2+ 9xSince both f(x) and g(x) have domains of (−∞,∞), the domain of fgis (−∞,∞).fg=x2+ 9x1 −x2where x2≠ 1Since the denominator equals zero whenever x2= 1, we must exclude ±1 from the domain. Thus,the domain of fgis (−∞,− 1)(−1, 1)(1, ∞).Question2:Score 5/5()()()()()()
Use the pair of functions to find f(g(x)) and g(f(x)). Simplify your answers.f(x) =x+ 8, g(x) =x2+ 1Reminder, to use sqrt(() to enter a square root. ).).
Question3:Score 5/5 Given f(x) =2 − 4xand g(x) = −1x, find the following:a.(gf)(x)Enclose numerators and denominators in parentheses. For example, (ab)/(1 +n).(gf)(x) = Your response b. the domain of (gf)(x) in interval notation.Enter the exact answer.To enter ∞, type infinity. To enter , type U.
• • • 