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Unformatted text preview: ' ~ ‘ EXAM 1
PHYS 1500: General Physics 1 (Sec. 001010)
February 2,2011 — Spring Semester, 2011 . VERSION 1 NAME: ‘< EY AU username: SEAT NUMBER: Instructions: Read each question CAREFULLY and answer all parts. Part 1: Multiple Choice and Short Problems (4 pts each) — 48 pts total 1) ' , 2) 3) t 4)
5) __ 6) __ 7) _____ 8)
9) , 10) . r . 1.1) . 12) Part 2; Extended Problems Problem 1: (22) Problem 2: (30) TOTAL: Exam 1 — Version 1 Page 1 of 8 Useful Equations and Quantities:
Acceleration due to gravity: ay = g = 9.8 m/s2 (i.e., vertical motion in a gravitational ﬁeld) Horizontal Motion 1 Vertical Motion
xf =x,.+vx",At+—CIXAt2 1 2 yf =y,+vy,.At~—gAt2
fo = Vx; + aXAt 2 v = v .— gAt
2 2 yf yr
Ver = in + Zax(xf —X,.) v2: vi, — 2g(yf — yl.) Eet=2l§=m5 sin(9) = 0—17?— Vector analysis: hy p
adj For: ax2+bx+c~=0 IAI=A= ’A:+Ay2 . 0049):};
————"” i “’2 '4‘” tame) =" f? me) = on: x* = 2a ad] Slope: m = Ay/Ax = (y2 — y1 )/(x2 — x1) Exam 1 — Version 1 i Page 2 of 8 Part 1: (6 pts each) Multiple Choice — Short Answer Problems For problems 1 through 4, consider the following vectors: yaxis (vertical)
lb l: o —x N —5—432‘ 0 1 2 3 4 5
X—axis (horizontal) 1) If the vector 3 is written in terms of its x and y components (Bx, By) it would be written as: O ' a) (3, 1) g l b) (4,—3) c) (3, 2) @ 2) What is the length (magnitude) of the vector A? W: W law; : 7.: :2 3) In terms of the components (x,y), what is: Zl — E: 1’4 @ b) (6, 1) . c) (6, 5) d) (0,5) 4) Relative to the +X'aXiS, What is the vector direction (angle) of vector 5 ?
C) .I i ‘ ‘— — S, O
Q: (CA4 [2‘7— 2 "{5A [3 a 3
‘ C3
9 5 S3: be. low 41x ~clxd as“ 3 O .7 Exam 1 — Version 1 I V Page 3 of 8 Problems 5 through 8 use the following figure. The graph below represents the velocity of a car that is
traveling along a long, straight road. ' velocity (m/s) “WWW!“MWWWWWWV v v , i WW‘AWWMWY‘ﬂWWW‘lW“W"will?“WWMWWWW‘WNWWMWWWWNW‘WWW .‘ ‘.x‘tummmmmmmmwammwwwmwmmmmmmmmmmmammmwwmmwyw MWMW .. v M. i» WM‘WWW‘WWMW'WWWWWMW c) 73  . d) Exam 1 — Version 1 Page 4 of 8 6)  What is the position of the car at t = 8 seconds? (tam. : (Sm/fﬂlgs): 37m 7) Between t = 10 seconds and t = 20 seconds, determine the acceleration of the car. 9, 91‘ 2 M :: °’——————~7‘% :vCZf/K/ISZ
U“ A9 gas—lag m: a 8) What is the displacement of the car between t = 23 seconds and t = 25 seconds? about: éi‘Zr)[253 7' “'2’” Exam 1 — Version 1 . Page 5 of 8 Problems 9 through 12 use the following figure of an object in twodimensional motion. Select one of
the five choices A through E as indicated below. 9) The acceleration vector at Point 1 is: A .r— l; 10) The vertical velocity vector at Point 3 is: 11) The velocity vector at Point 4 is: (3 A 12) The acceleration vector at Point 3 is: Exam 1 —Version 1 Page 6 of 8/ Extended Problem 1 (22 pts) 1) A football is kicked straight up into the air; it reaches a maximum height of 14.2 m. (a) With what speed did the football leave the kicker's foot? . C7 .0
K= ’L’gf 9:551: vi) C‘ W ‘ v we IéO7MZS
”33¢ = 113m: : ”ﬁg/WW") ‘ (b) What is the total time the football spent in the air? Assume it is kicked from ground level. Mﬂ‘lvtwcl i ’ M_£\QL&0(1‘:/Z
ﬂit/[Z “V39 ~1=ﬁm§bt~ialz
to; git 3 3:: 1,75 1};ng jg {5%
1?: 25:3“ 2 3,115 Exam 1 — Version 1 ' Page 7 of 8 Extended Problem 2 (30 pts) A ball is on top of a 2 2 m long, 1.3 m tall table. The ball is pushed along the table at a constant speed at
1.5 m/s. When it reaches the end of the table, it is moving horizontally. The ball then falls to the ground. a) How long does it take the ball to hit the ground? 9” 1
;1;~’= 1 11:11? J_1
‘jL‘Jg‘é ' 31"  (misglséc.
(:2 g " b) At What distance from the end of the table does the ball land? axz’ifvm— : Qs”*/33('as'/s”) : 0.771% c) What is the velocity vector of the ball when it lands? Give answer in terms of horizontal and vertical
components. W: 'l.§m{f Exam 1 — Version 1 Page 8 of 8 ...
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