University Physics with Modern Physics with Mastering Physics (11th Edition)

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10.59: a) A distance 4 L from the end with the clay. b) In this case 2 ) 3 4 ( ML I = and the gravitational torque is , sin ) 2 3 ( sin ) 2 )( 4 3 ( θ θ L Mg Mg L = so . sin ) 8 9 ( θ α L g = c) In this case 2 ) 3 1 ( ML I = and the gravitational torque is . sin ) 2 3 ( so , sin ) 2 ( sin ) 2 )( 4 ( θ α θ θ L g L Mg Mg L = =
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Unformatted text preview: d) The greater the angular acceleration of the upper end of the cue, the faster you would have to react to overcome deviations from the vertical....
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