10.60:
In Fig. (10.22) and Eq. (10.22), with the angle
θ
measured from the vertical,
θ
θ
cos
sin
=
in Eq. (10.2).
The torque is then
.
cos
θ
=
FR
τ
a)
∫
=
=
2
0
cos
π
FR
θ
d
θ
FR
W
b)
In Eq. (6.14),
dl
is the horizontal distance the point moves, and so
,
FR
dl
F
W
=
=
∫
the same as part (a).
c) From
.
4
,
)
4
(
2
2
2
MR
F
ω
ω
MR
W
K
=
=
=
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 Angular Acceleration, Physical quantities, α, 2 w, fr cos

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