problem10_60

University Physics with Modern Physics with Mastering Physics (11th Edition)

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10.60: In Fig. (10.22) and Eq. (10.22), with the angle θ measured from the vertical, θ θ cos sin = in Eq. (10.2). The torque is then . cos θ = FR τ a) = = 2 0 cos π FR θ d θ FR W b) In Eq. (6.14), dl is the horizontal distance the point moves, and so , FR dl F W = = the same as part (a). c) From . 4 , ) 4 ( 2 2 2 MR F ω ω MR W K = = =
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