10.64:
For a tension
T
in the string,
.
and
R
a
I
Iα
TR
ma
T
mg
=
=
=

Eliminating
T
and
solving for
a
gives
,
/
1
/
2
2
mR
I
g
R
I
m
m
g
a
+
=
+
=
where
m
is the mass of the hanging weight,
I
is the moment of inertia of the disk
combination
(
29
9.89
Problem
from
m
kg
10
25
.
2
2
3
⋅
×
=

I
and
R
is the radius of the disk to
which the string is attached.
a) With
m
= 1.50 kg,
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 Force, Mass, Moment Of Inertia, larger disk, disk combination

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