Then strong base takes us to the alkene now we need

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Unformatted text preview: to the ketone. Other ways to do this are possible, this is just one example. d. O Br2 hv Br PCC KOC(CH3)3 BH3 OH H2O2, NaOH Again, free radical halogenation starts us off. Then strong base takes us to the alkene. Now, we need the non-markovnikov alcohol which we know how to make with hydroboration. This gives us a primary alcohol which we can oxidze to the aldehyde using PCC. We can NOT use chromic acid in this step because it would over oxidize to the carboxylic acid 3 Sessler CH310N Homework Problem Set 2 Due Friday February 3rd, 2012 2. Draw the Mechanism for the acid catalyzed opening of an epoxide. H+ O OH H2O OH The epoxide is protonated by the acid Proton Transfer OH OH H2O Epoxide blocks top, so water can only attack from the back, similar to brominium ion OH2 H O H 4 Sessler CH310N Homework Problem Set 2...
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