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**Unformatted text preview: **10.72: (a) = I and a T = R PR = 1 1 a MR 2 = MR 2 T 2 2 R 2P 200 N aT = = = 50 m/s 2 M 4.00 kg 2 Distance the cable moves: x = 1 at 2 1 50 m = 50 m/s 2 t 2 t = 1.41 s. 2 v = v0 + at = 0 + 50 m/s2 (1.41 s ) = 70.5 m s ( ) ( ) (b) For a hoop, I = MR 2 , which is twice as large as before, so and a T would be 2 2 half as large. Therefore the time would be longer. For the speed, v = v0 + 2ax, in which x is the same, so v would be smaller since a is smaller ...

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