problem10_79

University Physics with Modern Physics with Mastering Physics (11th Edition)

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10.79: a) ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 s. m 34 . 9 kg 0590 . 0 7 m 15 . 0 m N 400 2 1 800 . 0 10 7 10 2 = = = m K v b) Twice the speed found in part (a), s. m 7 . 18 c) If the ball is rolling without slipping, the speed of a point at the bottom of the ball is zero. d) Rather than use the intermediate calculation of the speed, the fraction of the initial energy that was converted
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Unformatted text preview: to gravitational potential energy is ( 29 ( 29 ( 29 ( 29 mgh kx = 2 2 1 0.720 so , 900 . 800 . and solving for h gives 5.60 m....
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This document was uploaded on 02/04/2008.

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