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**Unformatted text preview: **10.82: Differentiating , and obtaining the answer to part (b), d = = 3bt 2 = 3b dt b
23 = 3b1 3 2 3 ,
13 =- d = 6bt = 6b dt b = 6b 2 3 1 3 . 9 I cmb 2 3 4 3 . 2 a a) W = I cm d = 6b 2 3 I cm 1 3d = c) The kinetic energy is 1 9 K = I cm 2 = I cm b 2 3 4 3 , 2 2 in agreement with Eq. (10.25); the total work done is the change in kinetic energy. ...

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