**Unformatted text preview: **. 4 kg 00 . 8 12 1 2 12 1 ⋅ = + = + = mr Ml I 2 1 2 m kg 4 . 153 ⋅ = = L L s rad 027 . 3 tot 2 = = I L ω Just after the collision the second ball has linear speed ( 29 ( 29 s m 055 . 6 s rad 027 . 3 m 00 . 2 = = = rw v and is moving upward. m 1.87 y gives 2 1 2 = = mgy mv for the height the second ball goes....

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