problem10_89

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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10.89: a) The initial angular momentum is ( 29 2 l mv L = and the final moment of inertia is ( 29 , 2 2 0 l m I I + = so ( 29 ( 29 ( 29 s. rad 46 . 5 2 3 2 2 2 = + = l m l M l mv ω b) ( 29 ( 29 , 2 1 2 I ω gh m M = + and after solving for h and substitution of numerical values, m. 10 16 . 3 2 - × = h c) Rather than recalculate the needed value of
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Unformatted text preview: ϖ , note that will be proportional to v and hence h will be proportional to ; 2 v for the board to swing all the way over, m. 250 . = h and so ( 29 s. m 1012 s m 360 m 0.0316 m 250 . = = v...
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