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**Unformatted text preview: **10.99: In Fig. (10.34(a)), if the vector r , and hence the vector L are not horizontal but make an angle with the horizontal, the torque will still be horizontal (the torque must be perpendicular to the vertical weight). The magnitude of the torque will be r cos , and this torque will change the direction of the horizontal component of the angular momentum, which has magnitude L cos . Thus, the situation of Fig. (10.36) is reproduced, but with L horiz instead of L . Then, the expression found in Eq. (10.36) becomes = d d L Lhoriz mgr cos r = = = = dt dt L cos Lhoriz ...

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